40=(2.5x)^(1/2)

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Solution for 40=(2.5x)^(1/2) equation:


D( x )

2.5*x < 0

2.5*x < 0

2.5*x < 0

2.5*x+0 < 0 // - 0

2.5*x < 0 // : 2.5

x < 0/2.5

x < 0

x in <0:+oo)

40 = (2.5*x)^(1/2) // - (2.5*x)^(1/2)

40-(2.5*x)^(1/2) = 0

-1*x^(1/2) = -40 // : -1

x^(1/2) = 40

( 40 < 0 i 1/2 in (0:1) ) => x należy do O

x belongs to the empty set

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